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f(-x) = f(x) <-- Even function
f(-x) = -f(x) <-- Odd function
In English, if you were to input a negative value of x into the
function f and you got the same output as if you were to input a
positive value of x it would be an even function. If you
input a negative x and the function outputs the opposite of a
positive x then it is an odd function. f (x) = a0xn + a1xn-1 + a2xn-2 + ... + an-1x + an
-- or even more mathematical:
That big "E" looking symbol is the Greek letter sigma and used to
represent a summation or a sum of values. I won't get into the use of this
right now and in fact this will hardly come up in differential calculus.
If I ever decide to write something on integrals and techniques of
integration the above symbol is used a lot. g(x)
f (x) = ----
h(x)
Note that since you can not divide anything by zero you must exclude
the value of x such that would make h (x) zero. There are two ways
a graph will act when approach that value of x which makes the
polynomial zero. Either the range will blow up quickly and go to infinity
(or negative-infinity) or it will merely "skip" that value of x.
The vertical line which goes through the point x when x
makes h (x) zero is called an asymptote. It's a line which the function
will approach but never equal. The point at which you have a division of
zero is called "undefined". f(x) = x2 - x + 2
g(x) = 3x - 4
-- all you need to do is plug in g(x) for every value of x
in function f
(f º g)(x) = (3x - 4)2 - (3x - 4) + 2
-- f.o.i.l. out the first term
(f º g)(x) = (9x2 - 12x + 16) - (3x - 4) + 2
-- combine like terms and simplify (final answer)
(f º g)(x) = 9x2 - 15x + 22
Evaluating composite functions is a little bit tricky, but still easy. There are actually two ways to do this so, I'll show you both and you can choose which one you like best. First let's start with a problem: f(x) = x2 - 2x + 4
g(x) = x + 2
-- evaluate the following
(f º g)(5)
-- One way of doing it: first find out what the composite
function is:
(f º g)(x) = (x + 2)2 - 2(x + 2) + 4
-- simplify
(f º g)(x) = x2 + 2x + 4
-- now plug in five for all the x's in the above function
(f º g)(5) = (5)2 + 2(5) + 4
= 39
-- Another way of doing it: first evaluate g(5):
g(5) = 7
-- plug the above into f(x) for all values of x:
f(7) = 72 - 2(7) + 4
= 39
We came up with the same answer, but used two different ways. Which
ever one you like best use. But, sometimes it will be better to use one
over the other so make sure you are comfortable with both. Later when we
get to the actual calculus work I will be using both ways
interchangeably.
This function graphs a quadratic for all values of x less than zero and a line for all values greater than or equal to zero. You can have any amount of functions, but I just used two. Interval Notation. This is used constantly in calculus. This is probably obvious, but an interval is merely a set of numbers between two other numbers (endpoints). You have an open interval which means that you are defining all the numbers between two numbers, but you are not including the two endpoints. An open interval is written like this: (a, b) ... this can be translated as for all values of x so that this remains true: a < x < b . So x is between a and b but never equal to. You also have a closed interval which means that you are defining all the numbers between two number including the two endpoints. A closed interval is written like this: [a, b] ... and can be translated as for all values of x so that this remains true: a £ x £ b . So x is between a and b including a and b. You can also have a combination of the two types of intervals. Take for instance: (a, b]. You are defining all numbers between a and b not including a and including b: a < x £ b . And you can create any type of combination you want. Something that most everybody gets wrong is when trying to define all numbers less than a certain number or all numbers greater than a certain number. An example of this would be: (-¥, a). This defines all numbers less than a but not equal to a. Note that I used an open interval for negative infinity because you can never get to negative infinity. Pass go and collect $200? Now it is time to decide what you want to do. You can either stop here and have a really good introduction to what you are going to need for calculus, or continue and go a little bit more in depth. Of course I suggest going more in depth, but the above should be enough for anything I write about calculus or kinematics, but you never know what else may come up. In the next part I am only going to be introducing power functions to add onto your list (polynomial and rational functions are on the list now)...that's all. It will be good experience for when we get to differentiation. If you do not read this next part skip down to the end to my conclusion. Collect $200... No money here but you definitely made the right decision if you chose to continue. This part will be pretty short so you do not need to worry about that. In the last part I introduced polynomial functions and rational functions. Now we are going to add power functions to the list. But first... About inverses and functions. Every function has an inverse. It is as easy as swapping your independent variable with your dependent variable. If given (y = 2x+3) its inverse would equal (y = x/2 - 3/2). All I did was swap y with x and then solve for y. However, not all inverses of functions are functions. Since we are only interested in functions we need to be able to tell if the inverse of a function is a function. This is what the horizontal line test was for. If a function passes the horizontal line test then its inverse is a function. Very easy. Also it should be noted that the inverse of any graph is always reflected of the line (y = x). The power function. Power functions are most commonly used in "money" problems. Example: you put $500 in the bank and it has an interest rate of 2 percent per annum. How much money will you have in three years. Problems like that. The power function is given with the following general form: f(x) = Crt ... where C can be thought of as a "starting" value, r as the growth rate, and t as the amount of time past. So just in case you are curious the answer to the above problem would be $530.60. Also this is a good time to throw in some properties of exponents because we will be using them a lot later on. And they are as follow: 1.) ax * ay = ax+y
ax
2.) ---- = ax-y
ay
1
3.) a-x = ----
ax
m ____
4.) am/n = \/ an
5.) (am)n = amn
Now some very important things to note about the function I gave
before the exponent properties. When I said that r represents the
growth rate there are actually two different types of growth rates: growth
and decay. When r is on the open interval (0, 1) then the function
represents "decay". When r is on the interval (1, ¥) the function represents "growth". Also note that we
are not concerned with negative values of r because the graph of
that function jumps around and is not continuous (a very important word in
calculus). I do not know if I mentioned this already, but calculus is
interested in functions that are "smooth" and do not jump all around. For
instance if you had the function: f(x) = -1x ... this function
jumps from a negative to a positive for every integer value of x
and has no defined values of f(x) between integer values of x ...
actually now that I think about it, it may not even be a
function. log525 = 2 , because 52 = 25
log327 = 3 , because 33 = 27
log1010 = 1 , because 101 = 10
So, in general, think of logarithms as another way of writing exponents. In fact, logarithms are exponents. You know how to go from a logarithm to an exponent, but can you do the opposite? Here are some examples: y = ax --> logay = x
y = 5x --> log5y = x
So we are comfortable with logarithms, hopefully. But, like I said
before, most of this stuff is just for your own reference so do not worry
if you do not fully get it. There are two bases of logarithms which have been given special names: the common and natural logarithm. The common logarithm is with base ten. If you ever see a logarithm written like (log 2) it is assumed to be a base of ten. The natural logarithm is with a base of 2.7182818 (...etc.). It may seem kind of weird to have a number like that for the base, but later we will see what an interesting number it is (much more interesting than p). The base of the natural logarithm goes on forever so it has been given the symbol of the Greek letter epsilon e. However, pretty much every book, article, paper, or text book related to math just uses the English letter e, and so will we. The natural logarithm has also been given a special notation, "ln" instead of "log". Since a logarithm is the inverse of a power function everything is flipped around. Where as before the range could never go below zero and the domain could be any real number, this time the domain never goes below zero and range can be any real number. Why's that? If you examine what a logarithm is you should see. The input of a logarithm is really what the "base" raised to the output should equal right? Well since there will never be a number such that a positive number raised to that power will result in a negative number you can never take the logarithm of a negative number. The graph of a logarithm is similar to that of a power function. Your asymptote for a logarithm (in the form: f(x) = logax) is at (x = 0). The domain is never less than zero nor is it ever equal to. Once again the base determines the type of slope you have. If the a is on the open interval (0, 1) the range will start in the positives and go down into the negatives. If the base is greater than one it will do just the opposite. Now for the part I like the best: properties of logarithms: loga1 = 0 , because a0 = 1
logaa = 1 , because a1 = a
logaax = x
alogax = x
loga(x*y) = logax + logay
loga(x/y) = logax - logay
// base conversion -- you can change the base of any logarithm, a,
to another base, b:
logbX
logaX = -----
logba
Most of those properties are similar to those of exponents so I do not
need to clarify them...except for the last one. Calculators can only
computer two kinds of logarithms: natural and common. You can use the last
property of logarithms to change the base of any arbitrary based logarithm
to anything you want. |