
Stinson Floatplane Technique Getting your underpowered Stinson off the water! Out of necessity, I've spent a great deal of time perfecting my takeoff technique with our modestly powered 165 hp 1082. As a novice, I tried desperately (and unsuccessfully) to force the plane onto the step. What experience has taught me, is to plan ahead, perfect your technique, and be patient! Under most conditions the aircraft will get on the step, and once on the step one seldom has a problem getting into the air. Here's a few points that may help you:
Note: I prefer lifting one float prior to reaching liftoff speed, but this should be avoided in rough water as it places undue stress on the float gear. Also, I immediately place the flap handle in the takeoff setting once off the water, then slowly and fully retract the flaps, allowing the airspeed to build to 80 mph IAS prior to initiating a climb. One should resist the temptation to attempt a climb below 80 mph when heavily loaded. I've found the added drag of the floats will prevent the aircraft from adequately accelerating if a climb is prematurely initiated. This can have disastrous results if attempting to clear an obstruction. On the other hand, once the aircraft reaches 80, decent climb performance is assured, and can easily be maintained. This is the formula used by EDO to determine the takeoff time (TOT) for proposed aircraft float combinations. I've presented it here, to show the theoretical difference between the 1082, 1083, and larger hp versions of the same aircraft. Where: Calculate PI Calculate TOT For the 1082 165 hp fixed pitch, on 2425s PI=2235/165 x sr of 2235/155 = 51.4359 TOT=1(2235/4850)^.3333 x (51.4359/25)^5 = 28.48 seconds For the 1083 165 hp fixed pitch, on 2425s PI=2500/165 x sr of 2500/155 = 60.8499 TOT=1(2500/4850)^.3333 x (60.8499/25)^5 = 68.496 seconds For the 1082 180 hp fixed pitch, on 2425s PI=2235/180 x sr of 2235/155 = 47.1496 TOT=1(2235/4850)^.3333 x (47.1496/25)^5 = 18.43 seconds For the 1083 210 hp c.s., on 2425s PI=2500/210 x sr of 2500/155 = 47.8107 TOT=0.93(2500/4850)^.3333 x (47.8107/25)^5 = 19.08 seconds For the 1082 210 hp c.s., on 2425s PI=2235/210 x sr of 2235/155 = 40.413936 TOT=0.93(2235/4850)^.3333 x (40.413936/25)^5 = 8.32 seconds.. wow! For the 1083 235 hp c.s., on 2870s PI=2500/235 x sr of 2500/155 = 42.724432 TOT=0.93(2500/5740)^.3333 x (42.724432/25)^5 = 10.28 seconds 
Send mail to flightlines@shaw.ca with
questions or comments about this web site.
