Here is a complete walkthrough: Cool

3/2 @ r12c6={12} (NP @ c6,n2)
Outies @ n4: r37c1=3={12} (NP @ c1)
Outies @ n6: r37c9=17={89} (NP @ c9)
Innies @ n1: r13c1=7=[52|61] => r17c1=[51|62]
Innies @ n9: r79c9=10=[82|91] => r39c9=[81|92]

Innie-outies @ n3: r3c6=r3c9-3
=> r3c69=[58|69]
Innie-outies @ n7: r7c4=r7c1+1
=> r7c14=[12|23] (2 @ r7 locked)

Innies @ n2: r23c5+r3c6=17 with r3c6=5|6
=> r23c5 can't have 5|6 (r23c5+r3c6 can't be {566})
=> r23c5=11|12={38|47|39|48}
r3c78=10-(5|6)=4|5={13|14|23}

Innies of whole grid: r1c1+r9c9=7=[52|61]
=> r1c1+r3c9=[59|68] => r1c1+r3c6=[56|65] form pointing pair
=> r1c45,r3c23 can't have {56}
=> HP @ r3: r3c46={56} (NP @ n2)
=> 11/2 @ r89c4={29|38|47} has 2|3|4

Innies @ n8: r7c4+r78c5=9 can't be {234} (11/2 @ r89c4)
=> r7c4+r78c5={126|135} => r78c5={15|16} (1 @ c5 locked)
=> r6c56=14-1-(5|6)=7|8 must be from {23456}
Also, since r6c6 is at least 3, r6c5 can't be 6

Now 14/4 @ c56 must be from {123456} with 1 locked
=> 14/4 @ c56={16(25|34)}
=> either r6c6 or r78c5 must have 6 (pointing cells)
=> r45c5, r789c6 can't have 6

Now since r9c5 is at least 2, r789c6 can't be {789} (25/4)
=> r789c6 must have at least one of {345}
Innies @ r1234: r1c1+r4c67=12 with r3c6=11-r1c1
=> r4c67=r3c6+1 => r3c6+r4c67=[542|634|643|652]

Innies @ c456: r3c6+r7c4=8=[53|62]
But r3c6+r7c4=[53] would force r34c6=[54], conflicts r789c6
=> r3c6+r7c4=[62] => r137c1=[521], r379c9=[982], r3c4=5
=> r78c5=9-2=7=[61], r3c78=10-6=4={13} (NP @ r3,n3)
=> 8/2 @ r12c3={17} (NP @ c3,n1) => HS @ r3: r3c5=7

r2c5=17-7-6=4 => r12c4 from {389} must have 3|8
=> 11/2 @ r89c4={47} (NP @ c4,n8 ) => HS @ c6,n5: r5c6=7
Now r6c56=14-6-1=7=[25|34] => r46c6 can't be [34]
=> 5 @ c6,n5 locked @ r46c6 => HS @ c5,n8: r9c5=5
=> r4c45=25-4-7=14=[68], r7c23=14-2=12=[75] (r7c6=3|9)

r4c89=16-9=7={25|34} => HSs @ r4: r4c123=[719]
=> r6c12=15-1=14={68} (NP @ r6,n4) => HSs @ c2: r58c2=[52]
Innies @ r6789: r6c34=7=[43] => r3c23=[48]
4 @ r7,n9 locked @ r7c78 => 11/2 @ r89c7=[56]
=> r89c3=[63] => r9c2=17-6-3=8

All naked singles from here.